-x^2+105x-1050=1550
We move all terms to the left:
-x^2+105x-1050-(1550)=0
We add all the numbers together, and all the variables
-1x^2+105x-2600=0
a = -1; b = 105; c = -2600; Ξ = b2-4ac Ξ = 1052-4Β·(-1)Β·(-2600) Ξ = 625 The delta value is higher than zero, so the equation has two solutions We use following formulas to calculate our solutions: x1=βbβΞβ2ax2=βb+Ξβ2a Ξβββ=625ββββ=25
x1=βbβΞβ2a=β(105)β252ββ1=β130β2=+65
x2=βb+Ξβ2a=β(105)+252ββ1=β80β2=+40