MATH SOLVE

4 months ago

Q:
# In slope-intercept form, what is the equation of a line perpendicular to y = 3x– 5 that passes through the point (-3, -6)?1. y = 3x – 72. y = 1/3x + 73. y = -1/3x – 74. y = -3x + 7

Accepted Solution

A:

Answer is 3

So we have a slope m = -1/3 and a point (-3,-6) so use the point slope formula (Y-Y1) = m(X-X1)In this case (X1,Y1) = (-3,-6) (Y -( -6) = (-1/3)(X-(-3) Y+6 = -1/3X-1 Y = -1/3X-7 would be the equation of the perpendicular line through (-3,-6)

So we have a slope m = -1/3 and a point (-3,-6) so use the point slope formula (Y-Y1) = m(X-X1)In this case (X1,Y1) = (-3,-6) (Y -( -6) = (-1/3)(X-(-3) Y+6 = -1/3X-1 Y = -1/3X-7 would be the equation of the perpendicular line through (-3,-6)