MATH SOLVE

4 months ago

Q:
# x^2 +105x-1050=1550please help

Accepted Solution

A:

-x^2+105x-1050=1550

We move all terms to the left:

-x^2+105x-1050-(1550)=0

We add all the numbers together, and all the variables

-1x^2+105x-2600=0

a = -1; b = 105; c = -2600;

Ξ = b2-4ac

Ξ = 1052-4Β·(-1)Β·(-2600)

Ξ = 625

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

x1=βbβΞβ2ax2=βb+Ξβ2a

Ξβββ=625ββββ=25 x1=βbβΞβ2a=β(105)β252ββ1=β130β2=+65 x2=βb+Ξβ2a=β(105)+252ββ1=β80β2=+40

-x^2+105x-1050=1550

We move all terms to the left:

-x^2+105x-1050-(1550)=0

We add all the numbers together, and all the variables

-1x^2+105x-2600=0

a = -1; b = 105; c = -2600;

Ξ = b2-4ac

Ξ = 1052-4Β·(-1)Β·(-2600)

Ξ = 625

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

x1=βbβΞβ2ax2=βb+Ξβ2a

Ξβββ=625ββββ=25 x1=βbβΞβ2a=β(105)β252ββ1=β130β2=+65 x2=βb+Ξβ2a=β(105)+252ββ1=β80β2=+40